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Question
Find which of the following number is cube of rational number \[\frac{125}{128}\] .
Sum
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Solution
We have: \[\frac{125}{128} = \frac{5 \times 5 \times 5}{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2} = \frac{5^3}{2^3 \times 2^3 \times 2}\]
\[\frac{125}{128}\] is not a cube of a rational number.
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