Question

Find the value of a line perpendicular to the given line 3x+4y = 13

Answer 1

When the lines are perpendicular to the product of their slopes is -1

i.e m₁ x m₂ = -1

3x + 4y = 13

4y = -3x + 13

y = `(-3)/4"x" + 13/4`

m₁ = `(-3)/4`

REquired slope = `(-1)/"m"_1 = 4/3`