Advertisements
Advertisements
Question
Find the value of the discriminant in the following quadratic equation :
10 x - `1/x` = 3
Advertisements
Solution
10 x - `1/x` = 3
10x2 - 3x - 1 = 0
Discriminant = b2 - 4ac
= (-3)2 - 4 (10) (-1)
= 9+ 40
= 49
APPEARS IN
RELATED QUESTIONS
Find the nature of the roots of the following quadratic equation. If the real roots exist, find them:
2x2 - 6x + 3 = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
2x2 + 3x + k = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
2x2 + kx + 2 = 0
Without solving the following quadratic equation, find the value of ‘p’ for which the given equation has real and equal roots:
x² + (p – 3) x + p = 0
Without actually determining the roots comment upon the nature of the roots of each of the following equations:
x2 - 5x + 7 = 0
Find the discriminant of the following equations and hence find the nature of roots: 3x2 – 5x – 2 = 0
If roots of a quadratic equation 3y2 + ky + 12 = 0 are real and equal, then find the value of ‘k’
(x2 + 1)2 – x2 = 0 has:
If α + β = 4 and α3 + β3 = 44, then α, β are the roots of the equation:
Find the roots of the quadratic equation by using the quadratic formula in the following:
–x2 + 7x – 10 = 0
