Advertisements
Advertisements
Question
Find the value of the discriminant in the following quadratic equation :
10 x - `1/x` = 3
Advertisements
Solution
10 x - `1/x` = 3
10x2 - 3x - 1 = 0
Discriminant = b2 - 4ac
= (-3)2 - 4 (10) (-1)
= 9+ 40
= 49
APPEARS IN
RELATED QUESTIONS
In the following determine the set of values of k for which the given quadratic equation has real roots:
3x2 + 2x + k = 0
If the roots of the equation (a2 + b2)x2 − 2 (ac + bd)x + (c2 + d2) = 0 are equal, prove that `a/b=c/d`.
If a, b, c are real numbers such that ac ≠ 0, then show that at least one of the equations ax2 + bx + c = 0 and -ax2 + bx + c = 0 has real roots.
Find the positive value(s) of k for which quadratic equations x2 + kx + 64 = 0 and x2 – 8x + k = 0 both will have real roots ?
Solve the following quadratic equation using formula method only :
x2 +10x- 8= 0
Find the value of k for which the following equation has equal roots:
(k − 12)x2 + 2(k − 12)x + 2 = 0.
Find the values of p for which the equation 3x2 – px + 5 = 0 has real roots.
The roots of the quadratic equation `2"x"^2 - 2sqrt2"x" + 1 = 0` are:
If the coefficient of x2 and the constant term of a quadratic equation have opposite signs, then the quadratic equation has real roots.
The roots of quadratic equation x(x + 8) + 12 = 0 are ______.
