Advertisements
Advertisements
Question
Find the volume of a cuboid whose diagonal is `3sqrt(29)"cm"` when its length, breadth and height are in the ratio 2 : 3 : 4.
Advertisements
Solution
Given that:
Diagonal of cuboid = `3sqrt(29)"cm"`...............................(1)
Ratio of Length, breadth & height = 2 : 3 : 4
∴ Length (l) = 2x
Breadth (b) = 3x &
Height (h) = 4x
We know that:
Diagonal of cuboid
= `sqrt("l"^2 + "b"^2 + "h"^2)`
= `sqrt((2x)^2 + (3x)^2 + (4x)^2)`
= `sqrt(4x^2 + 9x^2 + 16x^2)`
= `sqrt(29x^2)`
= `xsqrt(29)`
Also,
`xsqrt(29) = 3sqrt(29)` ...[From (1)]
i.e., x = `(3sqrt(29))/sqrt(29)`
∴ x = 3cm
Thus,
Length = 2 x 3 = 6cm
Breadth = 3 x 3 = 9cm
Height = 4 x 3 = 12cm
∴ Volume of cuboid
= l x b x h
= 6 x 9 x 12
= 54 x 12
= 648cm3.
APPEARS IN
RELATED QUESTIONS
The dimensions of a room are 12.5 m by 9 m by 7 m. There are 2 doors and 4 windows in the room; each door measures 2.5 m by 1 .2 m and each window 1 .5 m by I m. Find the cost of painting the walls at Rs. 3.50 per square metre.
What will happen to the volume of a cuboid if its Length is doubled, height is same and breadth is halved?
A closed iron tank 12 m long, 9 m wide and 4 m deep is to be made. Determine the cost of iron sheet used at the rate of Rs 5 per metre sheet, sheet being 2 m wide.
75 persons can sleep in a room 25 m by 9.6 m. If each person requires 16 m3 of the air; find the height of the room.
A closed box is cuboid in shape with length = 40 cm, breadth = 30 cm and height = 50 cm. It is made of a thin metal sheet. Find the cost of metal sheet required to make 20 such boxes, if 1 m2 of metal sheet costs Rs. 45.
Find the capacity of a cylindrical container with an internal diameter of 28 cm and a height of 20 cm.
The dimensions of a hall is 10 m × 9 m × 8 m. Find the cost of white washing the walls and ceiling at the rate of ₹ 8.50 per m2
All six faces of a cuboid are ______ in shape and of ______ area.
