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Question
A solid rectangular piece of iron measures 6 m by 6 cm by 2 cm. Find the weight of this piece, if 1 cm3 of iron weighs 8 gm.
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Solution
\[\text { The dimensions of the an iron piece is 6 m } \times 6 cm \times 2 cm, i . e . , 600 cm \times 6 cm \times 2 cm ( \because 1 m = 100 cm) . \]
\[\text { Its volume = 600 } \times 6 \times 2 = 7200 {cm}^3 \]
\[\text { Now, 1 }{cm}^3 = 8 gm\]
\[i . e . , 7200 {cm}^3 = 7200 \times 8 gm = 57600 gm\]
\[ \therefore \text { Weight of the iron piece = 57600 gm }\]
\[ = 57600 \times \frac{1}{1000}kg ( \because 1 Kg = 1000 gm)\]
\[ = 57 . 6 kg\]
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