Question

A cloassroom is 11 m long, 8 m wide and 5 m high. Find the sum of the areas of its floor and the four walls (including doors, windows, etc.)

Answer 1

\[\text { Lenght of the classroom = 11 m } \]

\[\text { Width = 8 m } \]

\[\text { Height = 5 m  }\]

\[\text { We have to find the sum of the areas of its floor and the four walls (i . e . , like an open box)  } \]

\[ \therefore \text { The sum of areas of the floor and the four walls = (length  }\times\text { width) } + 2 \times\text {  (width  }\times \text { height + length } \times\text {  height) }\]

\[ = (11 \times 8) + 2 \times (8 \times 5 + 11 \times 5)\]

\[ = 88 + 2 \times (40 + 55)\]

\[ = 88 + 190\]

\[ = 278 m^2\]