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Question
Find the values of x and y which satisfy the following equations (x, y ∈ R): (x + 2y) + (2x – 3y i + 4i = 5
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Solution
(x + 2y) + (2x – 3y i + 4i = 5
∴ (x + 2y) + (2x – 3y)i = 5 – 4i
Equating real and imaginary parts, we get
x + 2y = 5 ...(i)
and 2x - 3y = – 4 ...(ii)
Equation (i) x 2 – equation (ii) gives
7y = 14
∴ y = 2
Putting y = 2 in (i), we get
x + 2(2) = 5
∴ x + 4 = 5
∴ x = 1
∴ x = 1 and y = 2.
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