Question

Find the values of the following polynomials at a = –2 and b = 3:

`a/b + b/a`

Answer 1

Given, a = –2 and b = 3

So, putting a = –2 and b = 3 in the given expressions, we get

`a/b + b/a = ((-2))/3 + 3/((-2))`

= `(-2)/3 - 3/2`

= `(-4 - 9)/6`  ...[∵ LCM of 2 and 3 is 6]

= `(-13)/6`