Question

Find the values of the following polynomials at a = –2 and b = 3:

a² + 2ab + b²

Answer 1

Given, a = –2 and b = 3

So, putting a = –2 and b = 3 in the given expressions, we get  

a² + 2ab + b² = (–2)² + 2(–2)(3) + (3)²

= 4 – 12 + 9

= 1