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Question
Find the values of m and n if the following polynomial is a perfect square
`1/(x^4) - 6/(x^3) + 13/(x^2) + "m"/x + "n"`
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Solution
Since it is a perfect square
`1/x` (m + 12) = 0
m + 12 = 0
m = – 12
n – 4 = 0
n = 4
∴ The value of m = – 12 and n = 4
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