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Question
Find the values of following polynomials at m = 1, n = –1 and p = 2:
m2 + n2 + p2
Sum
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Solution
Given, m = 1, n = –1 and p = 2
So, putting m = 1, n = –1 and p = 2 in the given expressions, we get
m2 + n2 + p2 = (1)2 + (–1)2 + (2)2
= 1 + 1 + 4
= 6
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