Advertisements
Advertisements
Question
Find the value(s) of 'a' for which the quadratic equation x2 – ax + 1 = 0 has real and equal roots.
Advertisements
Solution
Given quadratic equation is x2 – ax + 1 = 0
On comparing it with ax2 + bx + c = 0, we get
a = 1, b = –a and c = 1
For real and equal roots, D = 0
i.e. b2 – 4ac = 0
⇒ (–a)2 – 4(1)(1) = 0
⇒ a2 – 4 = 0
⇒ a2 = 4
⇒ a = ±2
APPEARS IN
RELATED QUESTIONS
Find the values of k for which the quadratic equation (3k + 1) x2 + 2(k + 1) x + 1 = 0 has equal roots. Also, find the roots.
Determine the nature of the roots of the following quadratic equation:
`3/5x^2-2/3x+1=0`
Find the roots of the equation .`1/(2x-3)+1/(x+5)=1,x≠3/2,5`
Solve the following quadratic equation using formula method only :
x2 +10x- 8= 0
Find the value of k so that sum of the roots of the quadratic equation is equal to the product of the roots:
kx2 + 6x - 3k = 0, k ≠ 0
Discuss the nature of the roots of the following quadratic equations : `3x^2 - 4sqrt(3)x + 4` = 0
Which of the following equations has no real roots?
Choose the correct alternative answer for the following sub questions and write the correct alphabet.
If the root of the given quadratic equation are real and equal, then find the value of ‘k’ X2 + 2X + k = 0
Which of the following equations has two distinct real roots?
Solve the following quadratic equation:
x2 + 4x – 8 = 0
Give your Solution correct to one decimal place.
(Use mathematical tables if necessary.)
