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Question
Find the value of x in the following:
logx 8 = 6
Sum
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Solution
To solve logx 8 = 6, rewrite it in exponential form:
x6 = 8
Now take the sixth root of both sides:
`x = root(6)(8)`
Since 8 = 23, we get:
`x = root(6)(2^3)`
= `2^(3//6)`
= `2^(1//2)`
`x = sqrt(2)`
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