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Question
Find the value of x in the following figure, where O is the centre of the circle:

Sum
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Solution
Given:
∠BAD = 40°
∠ABD = 35°
We must find ∠ADC = x.
We must find ∠ADC = x.
Observe that A, B, C, and D are all points on the circle.
Step 1: Use triangle ABD
Triangle ABD is inside the circle.
∠BAD = 40°
∠ABD = 35°
Find ∠ADB (the angle at D inside triangle ABD):
Sum of angles of a triangle:
∠ADB = 180° − (40° + 35°)
∠ADB = 180° − 75°
∠ADB = 105°
So the angle at D between DA and DB is:
∠ADB = 105°.
Step 2: ∠ADB and ∠ACD subtend the same arc AB
Look at the circle:
∠ADB is an inscribed angle that subtends arc AB.
∠ACD (or the angle x region) is also an inscribed angle that subtends the same arc AB.
Therefore:
x = ∠ADB
x = 105°
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Chapter 15: Circles - Exercise 15A [Page 329]
