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Find the value of x in the following figure, where O is the centre of the circle: 35°, 40° - Mathematics

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प्रश्न

Find the value of x in the following figure, where O is the centre of the circle: 

योग
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उत्तर

Given:

∠BAD = 40°

∠ABD = 35°

We must find ∠ADC = x.

We must find ∠ADC = x.

Observe that A, B, C, and D are all points on the circle.

Step 1: Use triangle ABD

Triangle ABD is inside the circle.

∠BAD = 40°
∠ABD = 35°

Find ∠ADB (the angle at D inside triangle ABD):

Sum of angles of a triangle:

∠ADB = 180° − (40° + 35°)
∠ADB = 180° − 75°
∠ADB = 105°

So the angle at D between DA and DB is:

∠ADB = 105°.

Step 2: ∠ADB and ∠ACD subtend the same arc AB

Look at the circle:

∠ADB is an inscribed angle that subtends arc AB.

∠ACD (or the angle x region) is also an inscribed angle that subtends the same arc AB.

Therefore:

x = ∠ADB

x = 105°

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 15: Circles - Exercise 15A [पृष्ठ ३२९]

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नूतन Mathematics [English] Class 10 ICSE
अध्याय 15 Circles
Exercise 15A | Q 1. (vii) | पृष्ठ ३२९
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