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Question
Find the value of the following.
(−4)2
Sum
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Solution
(−4)2 = (−1)2 × (4)2 ...[since am × bm = (a × b)m]
= 1 × 16
= 16 ...[since (−1)n = 1 if n is even]
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Chapter 3: Algebra - Exercise 3.1 [Page 52]
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