Question

Find the value of `sec(tan^-1  y/2)`

Answer 1

Let `tan^-1  y/2` = θ

Where `theta ∈ (- pi/2, pi/2)`

So tan θ = `y/2`

Which gives sec θ = `sqrt(4 + y^2)/2`

Therefore, `sec(tan^-1  y/2)` = sec θ = `sqrt(4 + y^2)/2`.