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Question
Find the value of `log_3 1/9`.
Sum
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Solution
To find the value of `log_3 1/9`, express `1/9`as a power of 3:
`9 = 3^2 ⇒ 1/9 = 3^-2`
So, `log_3(1/9) = log_3(3^-2) = -2`
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Chapter 7: Logarithms - EXERCISE 7A [Page 72]
