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Question
Find the value of: `"log" _(1/5) 125` = x
Sum
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Solution
`"log" _(1/5) 125`
Let `"log"_(1/5) 125` = x
⇒ `(1/5)^x` = 125
⇒ 5-x = 53
∴ - x = 3
⇒ x = -3.
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Interchanging Logarithmic and Exponential Forms - Logarithmic to Exponential
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