Question

Find the value of 'k' so that the quadratic equation 3x² – 5x – 2k = 0 has real and equal roots.

Answer 1

Given quadratic equation is 3x² – 5x – 2k = 0

For real and equal roots D = 0; i.e., b² – 4ac = 0

On comparing the given equation with ax² + bx + c = 0, we get

a = 3, b = –5 and c = –2k

∴ b² – 4ac = 0

⇒ (–5)² – 4(3)(–2k) = 0

⇒ 25 + 24k = 0

⇒ k = `- 25/24`