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Question
Find the total surface area of frustum, if its radii are 15 cm and 7 cm. Also, the slant height of the frustum is 14 cm.
Radii of the frustum = `square` cm and `square` cm
Slant height of the frustum = `square` cm
Total surface area = `π[(r_1^2 + r_2^2 + (r_1 + r_2)l]`
= `22/7 [square + square + (square + square) square]`
= `22/7 (square)`
= `square` cm2
Hence, the total surface area of the frustum is `square`.
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Solution
Radii of the frustum = 15 cm and 7 cm
Slant height of the frustum = 14 cm
Total surface area = `π[(r_1^2 + r_2^2 + (r_1 + r_2)l]`
= `22/7` [(15)2 + (7)2 + (15 + 7) 14]
= `22/7 (bb582)`
= 1829.14 cm2
Hence, the total surface area of the frustum is 1829.14 cm2.
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