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Question
Find the sum of the first 200 even natural numbers.
Sum
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Solution
The even natural numbers are 2, 4, 6, 8, ....
a = 2
d = 4 − 2
= 2
n = 200
`S_n = n/2 [2a + (n - 1)d]`
`S_200 = 200/2 [2(2) + (200 - 1)2]`
= 100[4 + 199 × 2]
= 100[4 + 398]
= 100 × 402
= 40,200
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