Advertisements
Advertisements
Question
Find the slope of tangent to the curve y = 2 cos2(3x) at `x = π/6`.
Sum
Advertisements
Solution
`dy/dx = 2 xx 2 xx cos(3x) xx (-sin 3x) xx 3`
`dy/dx = 6 sin 6x`
`dy/dx]_(x = π/6) = -6 sin π`
= – 6 × 0
= 0
shaalaa.com
Is there an error in this question or solution?
