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Question
Find the ratio of the intensities of lights with wavelengths 500 nm and 300 nm which undergo Rayleigh scattering.
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Solution
λ1 = 500
λ2 = 300 nm
`"I" prop 1/lambda^4`
`"I"_1/"I"_2 = ((lambda_2)/(lambda_1))^4`
`"I"_1/"I"_2 = (300/500)^4`
`"I"_1/"I"_2 = (3/5)^4`
`"I"_1/"I"_2 = 81/625`
`"I"_1: "I"_2 = 81 : 625`
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