Advertisements
Advertisements
Question
Derive the equation for effective focal length for lenses in contact.
Advertisements
Solution

Lenses in contact
- Two lenses (1) and (2) having focal length are placed coaxially in contact.
- Lens equation for first equation be
`1/"v'" - 1/"u" = 1/"f"_1` - Lens equation for the second lens be
`1/"v" − 1/"v′" = 1/"f"_2` - Adding the above equation
`1/"v" - 1/"u" = 1/"f"_1 + 1/"f"_2` - If the combinations acts as single lens then,
`1/"v" - 1/"u" = 1/"f"` - On comparing,
`1/"F" = 1/"f"_1 + 1/"f"_2`
∴ For any number of lens in contact
`1/"f"_1 + 1/"f"_2 + 1/"f"_3 + ....`
APPEARS IN
RELATED QUESTIONS
What are primary focus and secondary focus of convex lens?
What are the sign conventions followed for lenses?
Arrive at lens equation from lens maker’s formula.
Obtain the equation for lateral magnification for thin lens.
Obtain lens maker’s formula and mention its significance.
Derive the equation for thin lens and obtain its magnification.
Derive the equation for effective focal length for lenses in out of contact.
If the distance D between an object and screen is greater than 4 times the focal length of a convex lens, then there are two positions of the lens for which images are formed on the screen. This method is called conjugate foci method. If d is the distance between the two positions of the lens, obtain the equation for a focal length of the convex lens.
A point object is placed at 20 cm from a thin plano-convex lens of focal length 15 cm whose plane surface is silvered. Locate the position and nature of the final image.
Find the ratio of the intensities of lights with wavelengths 500 nm and 300 nm which undergo Rayleigh scattering.
