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Question
Find the product of (y2 – 4)(2y2 + 3y)
Sum
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Solution
(y2 – 4)(2y2 + 3y) = y2(2y2 + 3y) – 4(2y2) – 4(3y)
= y2(2y2) + y2 (3y) – 4(2y2) – 4(3y)
= 2y4 + 3y3 – 8y2 – 12y
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Chapter 3: Algebra - Exercise 3.1 [Page 81]
