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Question
Find the principal value of the following:
`cot^(-1) (sqrt3)`
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Solution
Let `cot^(-1) (sqrt3)` = y
Then cot y = `sqrt3 = cot (pi/6)`
We know that the range of the principal value branch of cot−1 is (0, π).
Then `cot (pi/6) = sqrt3`
Where `pi/6 ∈ (0, pi)`
Therefore, the principal value of `cot^(-1) (sqrt3)` is `pi/6`.
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