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Find the principal value of the following: cot-1(sqrt3) - Mathematics

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Question

Find the principal value of the following:

`cot^(-1) (sqrt3)`

Sum
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Solution

Let `cot^(-1) (sqrt3)` = y

 Then cot y = `sqrt3 = cot (pi/6)`

We know that the range of the principal value branch of cot−1 is (0, π). 

Then `cot (pi/6) = sqrt3`

Where `pi/6 ∈ (0, pi)`

Therefore, the principal value of `cot^(-1) (sqrt3)` is `pi/6`.

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Chapter 2: Inverse Trigonometric Functions - Exercise 2.1 [Page 42]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 2 Inverse Trigonometric Functions
Exercise 2.1 | Q 8 | Page 42

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