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Question
Find the number which bears the same ratio to `7/33` that `8/21` does to `4/9`.
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Solution
Let the required number be `x/y`
Now, ratio of `8/21` to `4/9`
= `(8/21)/(4/9)`
= `8/21 xx 9/4`
= `6/7`
Thus, we have
`(x/y)/(7/33) = 6/7`
`=> x/y = (6/7)/(7/33)`
`=> x/y = 6/7 xx 7/33`
`=> x/y = 2/11`
Hence, the required number is `2/11`.
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