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Question
Find the number of arrangements of letters in the word MUMBAI so that the letter B is always next to A
Sum
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Solution
In the word MUMBAI the number of letters is n = 6 of which M repeats twice, i.e., p = 2.
If B is always next to A, i.e., AB, then it forms one unit and remaining 4 letters. Therefore total number of letters n = 5 and p = 2.
∴ number of different ways of arrangements of letters in which B is always next to A
= `("n"!)/("p"!)`
= `(5!)/(2!)`
= `120/2`
= 60.
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