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Question
Find the mean by step deviation method:
| Class | 10 – 15 | 15 – 20 | 20 – 25 | 25 – 30 | 30 – 35 | 35 – 40 |
| Frequency | 5 | 6 | 8 | 12 | 6 | 5 |
Sum
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Solution
1. Identify the formula
The formula for the mean `(barx)` using the step deviation method is:
`barx = A + ((sumf_iu_i)/(sumf_i)) xx h`
Where:
A: Assumed mean a value from the middle of the class marks.
h: Class size width of the interval, e.g., 15 – 10 = 5.
fi: Frequency of each class.
xi: Class mark (midpoint) of each class `(("Lower Limit" + "Upper Limit")/2)`.
ui: Step deviation, calculated as `u_i = (x_i -A)/h`.
2. Calculation table
We will pick A = 22.5 as our assumed mean.
| Class | Frequency (fi) |
Class Mark (xi) |
`bb(u_i = (x_i - 22.5)/5)` | fiui |
| 10 – 15 | 5 | 12.5 | –2 | –10 |
| 15 – 20 | 6 | 17.5 | –1 | –6 |
| 20 – 25 | 8 | 22.5 (A) | 0 | 0 |
| 25 – 30 | 12 | 27.5 | 1 | 12 |
| 30 – 35 | 6 | 32.5 | 2 | 12 |
| 35 – 40 | 5 | 37.5 | 3 | 15 |
| Total | Σfi = 42 | Σfiui = 23 |
3. Final calculation
Now, substitute the values into the formula:
`barx = 22.5 + (23/42) xx 5`
`barx = 22.5 + 115/42`
`barx ≈ 22.5 + 2.738`
`barx ≈ 25.238`
The mean of the given data is approximately 25.24.
shaalaa.com
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