मराठी

Find the mean by step deviation method: Class 10 – 15 15 – 20 20 – 25 25 – 30 30 – 35 35 – 40 Frequency 5 6 8 12 6 5 - Mathematics

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प्रश्न

Find the mean by step deviation method:

Class 10 – 15 15 – 20 20 – 25 25 – 30 30 – 35 35 – 40
Frequency 5 6 8 12 6 5
बेरीज
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उत्तर

1. Identify the formula

The formula for the mean `(barx)` using the step deviation method is:

`barx = A + ((sumf_iu_i)/(sumf_i)) xx h`

Where:

A: Assumed mean a value from the middle of the class marks.

h: Class size width of the interval, e.g., 15 – 10 = 5.

fi: Frequency of each class.

xi: Class mark (midpoint) of each class `(("Lower Limit" + "Upper Limit")/2)`.

ui: Step deviation, calculated as `u_i = (x_i -A)/h`.

2. Calculation table

We will pick A = 22.5 as our assumed mean.

Class Frequency
(fi)
Class Mark
(xi)
`bb(u_i = (x_i - 22.5)/5)` fiui
10 – 15 5 12.5 –2 –10
15 – 20 6 17.5 –1 –6
20 – 25 8 22.5 (A) 0 0
25 – 30 12 27.5 1 12
30 – 35 6 32.5 2 12
35 – 40 5 37.5 3 15
Total Σfi = 42     Σfiui = 23

3. Final calculation

Now, substitute the values into the formula:

`barx = 22.5 + (23/42) xx 5`

`barx = 22.5 + 115/42`

`barx ≈ 22.5 + 2.738`

`barx ≈ 25.238`

The mean of the given data is approximately 25.24.

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पाठ 21: Measures of central tendency - Exercise 21A [पृष्ठ ४६२]

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नूतन Mathematics [English] Class 10 ICSE
पाठ 21 Measures of central tendency
Exercise 21A | Q 9. | पृष्ठ ४६२
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