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Question
Find the length of the chord AC where AB and CD are the two diameters perpendicular to each other of a circle with radius `4sqrt(2)` cm and also find ∠OAC and ∠OCA
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Solution
Radius of a circle = `4sqrt(2)` cm
In the right ΔAOC,
AC2 = OA2 + OC2
AC2 = `(4sqrt(2))^2 + (4sqrt(2))^2`
= 32 + 32 = 64
AC = `sqrt(64)`
= 8
Length of the chord = 8 cm,
∠OAC = ∠OCA = 45°
Since OAC is an isosceles right angle triangle.
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