Advertisements
Advertisements
Question
Find the LCM and HCF of the following integers by applying the prime factorisation method.
12, 15 and 21
Advertisements
Solution
 |
 |
 |
12 = 2 × 2 × 3
15 = 3 × 5
21 = 3 × 7
H.C.F of 12, 15 and 21 = 3
L.CM of 12, 15 and 21 = 2 × 2 × 3 × 5 × 7
L.C.M of 12, 15 and 21 = 420
RELATED QUESTIONS
Find the LCM and HCF of the following integers by applying the prime factorisation method:
84, 90 and 120
Can two numbers have 16 as their HCF and 380 as their LCM? Give reason.
Write down the decimal expansions of the following rational numbers by writing their denominators in the form 2m × 5n, where m, n are non-negative integers.
\[\frac{13}{125}\]
State Fundamental Theorem of Arithmetic.
Express the number as a product of its prime factor:
7429
Find the LCM and HCF of the following pair of integers and verify that LCM × HCF = product of the two numbers.
510 and 92
Find the LCM and HCF of the following pair of integers and verify that LCM × HCF = product of the two numbers.
336 and 54
If m, n are natural numbers, for what values of m, does 2n × 5m ends in 5?
Find the H.C.F. of 252525 and 363636
Find the L.C.M. and H.C.F. of 408 and 170 by applying the fundamental theorem of Arithmetic
Express 98 as a product of its primes.
Three farmers have 490 kg, 588 kg and 882 kg of wheat respectively. Find the maximum capacity of a bag so that the wheat can be packed in exact number of bags.
When a number is divided by 7, its remainder is always ______.
If LCM(x, 18) = 36 and HCF(x, 18) = 2, then x is ______.
For some integer q, every odd integer is of the form ______.
If the HCF of 65 and 117 is expressible in the form 65m – 117, then the value of m is ______.
The least number that is divisible by all the numbers from 1 to 10 (both inclusive) is ______.
If n is a natural number, then 8n cannot end with digit
The prime factorisation of the number 5488 is ______.
