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Question
Find the interval in which the function f(x) = x4 – 4x3 + 10 is strictly decreasing.
Sum
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Solution
We have f(x) = x4 − 4x3 + 10
⇒ f'(x) = 4x3 − 12x2
⇒ f'(x) = 4x2 (x − 3)
For f(x) is strictly decreasing, we must have f'(x) < 0
Value of x is 0, 3

Strictly Decreasing (-∞, 0) ∪ (0, 3)
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