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Find the integrals of the function: sin3 (2x + 1) - Mathematics

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Question

Find the integrals of the function:

sin3 (2x + 1)

Sum
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Solution

Let `I = int sin^3 (2x + 1)` dx

`= 1/4 [3 sin (2x + 1) - sin 3 (2x + 1)]` dx

        .....`[because sin^3 theta = 1/4 (3 sin theta - sin 3 theta)]`

`= 3/4 (- (cos (2x + 1))/2 - 1/4 ((- cos 3 (2x + 1))/6) + C`

`= -3/8  cos (2x + 1) + 1/24  cos 3 (2x + 1) + C`

`= - 3/8  cos (2x + 1) + 1/24 [4 cos^3 (2x + 1) - 3 cos (2x + 1) + C`      ......`[because  cos 3 theta = 4 cos^3 theta - 3 cos theta]`

`= - 3/8  cos (2x + 1) + 1/6  cos^3 (2x + 1) - 1/8  cos(2x + 1) + C`

`= - 1/2  cos (2x + 1) + 1/6  cos^3 (2x + 1) + C`

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Chapter 7: Integrals - Exercise 7.3 [Page 307]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 7 Integrals
Exercise 7.3 | Q 4 | Page 307

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