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Find the integrals of the function: sin x sin 2x sin 3x

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Question

Find the integrals of the function:

sin x sin 2x sin 3x

Sum
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Solution

Let `I = int sin x sin 2x sin 3x  dx`

`= 1/2 int (2 sin x sin 2x) sin 3x  dx`

`= 1/2 int (cos x - cos 3x) sin 3x  dx`       ... [∵ 2 sin A sin B =  cos (A - B) - cos (A + B)]

`= 1/4 int 2 sin 3x cos x  dx - 1/4 int 2 sin 3x cos 3x dx`   .... [∵ 2 sin A cos B = sin (A + B) + sin (A - B)]

`= 1/4 int (sin 4x + sin 2x) dx - 1/4 int sin 6x dx`

`= -1/16 cos 4x - 1/8 cos 2x + 1/24 cos 6x + C`

`= 1/4 [1/6 cos 6x - 1/4 cos 4x - 1/2 cos 2x] + C`

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Chapter 7: Integrals - Exercise 7.3 [Page 307]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 7 Integrals
Exercise 7.3 | Q 6 | Page 307

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