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Find the HCF and LCM of 8/9,10/27 and 16/81.

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Question

Find the HCF and LCM of `8/9, 10/27` and `16/81`.

Sum
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Solution

Given: `8/9, 10/27` and `16/81`

Step-wise calculation:

1. Use the rules for fractions:

HCF of fractions = `"HCF (numerators)"/"LCM (denominators)"`

LCM of fractions = `"LCM (numerators)"/"HCF (denominators)"`

2. Prime-factorise:

Numerators: 8 = 23

10 = 2 × 5

16 = 24

HCF (numerators) = `2^min(3, 1, 4) = 2` 

LCM (numerators) = `2^max(3, 1,4) xx 5` 

= 24 × 5

= 16 × 5

= 80

Denominators: 9 = 32

27 = 33

81 = 34 

HCF(denominators) = `3^min(2, 3, 4)`

= 32

= 9 

LCM(denominators) = `3^max(2, 3, 4)`

= 34

= 81

3. Apply the formulas:

HCF = `"HCF (numerators)"/"LCM (denominators)"`

= `2/81`

LCM = `"LCM (numerators)"/"HCF (denominators)"`

= `80/9`

HCF `(8/9, 10/27, 16/81) = 2/81`

LCM `(8/9, 10/27, 16/81) = 80/9`

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Chapter 1: Real Numbers - TEST YOURSELF [Page 45]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 1 Real Numbers
TEST YOURSELF | Q 15. | Page 45
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