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Question
Find the HCF and LCM of `8/9, 10/27` and `16/81`.
Sum
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Solution
Given: `8/9, 10/27` and `16/81`
Step-wise calculation:
1. Use the rules for fractions:
HCF of fractions = `"HCF (numerators)"/"LCM (denominators)"`
LCM of fractions = `"LCM (numerators)"/"HCF (denominators)"`
2. Prime-factorise:
Numerators: 8 = 23
10 = 2 × 5
16 = 24
HCF (numerators) = `2^min(3, 1, 4) = 2`
LCM (numerators) = `2^max(3, 1,4) xx 5`
= 24 × 5
= 16 × 5
= 80
Denominators: 9 = 32
27 = 33
81 = 34
HCF(denominators) = `3^min(2, 3, 4)`
= 32
= 9
LCM(denominators) = `3^max(2, 3, 4)`
= 34
= 81
3. Apply the formulas:
HCF = `"HCF (numerators)"/"LCM (denominators)"`
= `2/81`
LCM = `"LCM (numerators)"/"HCF (denominators)"`
= `80/9`
HCF `(8/9, 10/27, 16/81) = 2/81`
LCM `(8/9, 10/27, 16/81) = 80/9`
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