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Find the HCF and LCM of 12, 15, 18, 27.

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Question

Find the HCF and LCM of 12, 15, 18, 27.

Numerical
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Solution

Given: 12, 15, 18, 27.

Step-wise calculation:

1. Prime factorise each:

12 = 22 × 3

15 = 3 × 5

18 = 2 × 32

27 = 33

2. HCF: Take common primes with smallest exponents:

Only 3 is common; smallest exponent = 1 → HCF = 31 = 3.

3. LCM: Take all primes with largest exponents:

22 (from 12), 33 (from 27), 51 (from 15) → LCM = 22 × 33 × 5

Compute: 4 × 27 × 5

= 108 × 5 

= 540

HCF = 3, LCM = 540.

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Chapter 1: Real Numbers - TEST YOURSELF [Page 45]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 1 Real Numbers
TEST YOURSELF | Q 11. | Page 45
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