Advertisements
Advertisements
Question
Find the greatest number that will divide 445, 572 and 699, leaving remainders 4, 5, 6 respectively.
Advertisements
Solution
Since the respective remainders of 445, 572, and 699 are 4, 5, and 6, we have to find the number which exactly divides (445-4), (572-5), and (696-6).
So, the required number is the HCF of 441, 567, and 693.
Firstly, we will find the HCF of 441 and 567.
∴ HCF = 63
Now, we will find the HCF of 63 and 693.
∴ HCF = 63
Hence, the required number is 63.
APPEARS IN
RELATED QUESTIONS
Test the divisibility of the following number by 3:
79124
Test the divisibility of the following numbers by 5:
723405
Test the divisibility of the following numbers by 6:
46523
Test the divisibility of the following numbers by 7:
14126
Test the divisibility of the following numbers by 9:
257106
Test the divisibility of the following number by 11:
901351
In the following number, replace * by the smallest number to make it divisible by 9:
6678*1
State if the following is a prime number?
179
Give an example of a number which is divisible by both 2 and 8 but not by 16.
Write (T) for true and (F) for false against the following statement:
If a number is divisible by 4, it must be divisible by 8.
