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Find the greatest number of four digits which is exactly divisible by 15, 24 and 36.

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Question

Find the greatest number of four digits which is exactly divisible by 15, 24 and 36.

Numerical
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Solution

Prime factorization:

15 = 3 × 5

24 = 23 × 3

36 = 22 × 3

LCM = product of greatest power of each prime factor involved in the numbers = 23 × 32 × 5 = 360 

Now, the greatest four digit number is 9999.

On dividing 9999 by 360 we get 279 as remainder.

Thus, 9999 – 279 = 9720 is exactly divisible by 360.

Hence, the greatest number of four digits which is exactly divisible by 15, 24 and 36 is 9720.

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Chapter 1: Real Numbers - EXERCISE 1B [Page 18]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 1 Real Numbers
EXERCISE 1B | Q 20. | Page 18
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