Advertisements
Advertisements
Question
Find the G.C.D for the following:
ab2c3, a2b3c, a3bc2
Sum
Advertisements
Solution
ab2c3 = a × b2 × c3
a2b3c = a2 × b3 × c
a3bc2 = a3 × b × c2
G.C.D = abc
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Find the prime factor of the following numbers and find their LCM and HCF.
153, 187
Find the HCF of the numbers in each of the following, using the prime factorization method:
170, 238
Find the HCF of the numbers in each of the following, using the division method:
658, 940, 1128
Show that the following pairs are co-primes:
59, 97
Find the G.C.D of the following:
am+1, am+2, am+3
Find the G.C.D of the following:
a3 – 9ax2, (a – 3x)2
What is the HCF of two consecutive odd numbers?
Find the HCF of the following numbers:
30, 42
Find the HCF of the following numbers:
27, 63
Find the HCF of the following numbers:
12, 45, 75
