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Find the focal distance of a point on the parabola y2 = 16x whose ordinate is 2 times the abscissa - Mathematics and Statistics

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Question

Find the focal distance of a point on the parabola y2 = 16x whose ordinate is 2 times the abscissa

Sum
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Solution

Given equation of the parabola is y2 = 16x

Comparing this equation with y2 = 4ax, we get

4a = 16

∴ a = `16/4` = 4

 Since ordinate is 2 times the abscissa,

y = 2x

Substituting y = 2x in y2 = 16x, we get

(2x)2 = 16x

∴ 4x2 = 16x

∴ 4x2 – 16x = 0

∴ 4x(x – 4) = 0

∴ x = 0 or x = 4,

When x = 4,

focal distance = x + a = 4 + 4 = 8

When x = 0,

focal distance = a = 4

∴ Focal distance is 4 or 8.

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Conic Sections - Parabola
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Chapter 7: Conic Sections - Exercise 7.1 [Page 149]

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