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Question
Find the feasible solution of the following inequation:
3x + 2y ≤ 18, 2x + y ≤ 10, x ≥ 0, y ≥ 0
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Solution
| Given inequalities | 3x + 2y ≤ 18 | 2x + y ≤ 10 |
| Corresponding equalities | 3x + 2y = 18 | 2x + y = 10 |
| Intersection of line with X-axis | A(6, 0) | C(5, 0) |
| Intersection of line with Y-axis | B(0, 9) | D(0, 10) |
| Origin test |
3(0) + 2(0) ≤ 18 i.e., 0 ≤ 18 which is true |
2(0) + 0 ≤ 10 i.e., 0 ≤ 10 which is true |
| Region | Origin side of the line | Origin side of the line |
x ≥ 0, y ≥ 0 represent 1st quadrant.
The shaded portion represents the feasible solution.
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