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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Find the equation of the pair of straight lines passing through the point (1, 3) and perpendicular to the lines 2x − 3y + 1 = 0 and 5x + y − 3 = 0

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Question

Find the equation of the pair of straight lines passing through the point (1, 3) and perpendicular to the lines 2x − 3y + 1 = 0 and 5x + y − 3 = 0

Sum
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Solution


Equation of a line perpendicular to 2x – 3y + 1 = 0 is of the form 3x + 2y + k = 0.

It passes through (1, 3)

⇒ 3 + 6 + k = 0

⇒ k = – 9

So the line is 3x + 2y – 9 = 0

The equation of a line perpendicular to 5x + y – 3 = 0 will be of the form x – 5y + k = 0.

It passes through (1, 3)

⇒ 1 – 15 + k = 0

⇒ k = 14

So the line is x – 5y + 14 = 0.

The equation of the lines is 3x + 2y – 9 = 0 and x – 5y + 14 = 0

Their combined equation is (3x + 2y – 9)(x – 5y + 14) = 0
(i.e) 3x2 – 15xy + 42x + 2xy – 10y2 + 28y – 9x + 45y – 126 = 0

(i.e) 3x2 – 13xy – 10y2 + 33x + 73y – 126 = 0

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Pair of Straight Lines
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Chapter 6: Two Dimensional Analytical Geometry - Exercise 6.4 [Page 281]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 6 Two Dimensional Analytical Geometry
Exercise 6.4 | Q 6 | Page 281

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