Question

Find the equation of the line with x-intercept 5 and a point on it (–3, 2).

Answer 1

Since, x-intercept is 5, so the corresponding point on x-axis is (5, 0).

The line also passes through (–3, 2).

∴ Slope of the line = `(2 - 0)/(-3 - 5) = 2/-8 = (-1)/4`

Required equation of the line is given by:

y – y₁ = m(x – x₁)

`y - 0 = (-1)/4 (x - 5)`

4y = –x + 5

x + 4y = 5