Question

Find the equation of the line passing through the points (4,-5) and (-1,-2).

Answer 1

Equation of line passing through points (x₁,y₁) and (x₂,y₂) is given by

`(x - x_1)/(x_1 - x_2) = (y - y_1)/(y_1 - y_2)`

Here (x₁,y₁) = (4,-5) and (x₂,y₂) = (-1,-2)

Equation of line passing through (4,-5) and (-1,-2) is given by

`(x - 4)/(4 - (-1)) = (y - (-5))/((-5) - (-2))`

∴ `(x - 4)/5 = (y + 5)/-3`

∴ (-3)(x-4) = 5(y + 5)

∴ - 3x + 12 = 5y + 25

∴ 12 – 25 = 5y + 3x

∴ 3x + 5y = - 13

∴ 3x + 5y + 13 = 0

Therefore equation of line passing through (4,-5) and (-1,-2) is 3x + 5y + 13 = 0