English

Find the equation of the hyperbola satisfying the given conditions: Vertices (0, ±5), foci (0, ±8)

Advertisements
Advertisements

Question

Find the equation of the hyperbola satisfying the given conditions:

Vertices (0, ±5), foci (0, ±8)

Sum
Advertisements

Solution

Vertices (0, ±5), foci (0, ±8)

Here, the vertices are on the y-axis.

Therefore, the equation of the hyperbola is of the form `y^2/a^2 - x^2/b^2 = 1`.

Since the vertices are (0, ±5), a = 5.

Since the foci are (0, ±8), c = 8.

We know that a2 + b2 = c2.

∴ 52 + b2 = 82

b2 = 64 - 25 = 39

Thus, the equation of the hyperbola is `y^2/25 - x^2/39 = 1`.

shaalaa.com
  Is there an error in this question or solution?
Chapter 10: Conic Sections - EXERCISE 10.4 [Page 202]

APPEARS IN

NCERT Mathematics [English] Class 11
Chapter 10 Conic Sections
EXERCISE 10.4 | Q 8. | Page 202
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×