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Find the equation of the hyperbola satisfying the given conditions: Vertices (0, ±5), foci (0, ±8) - Mathematics

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Question

Find the equation of the hyperbola satisfying the given conditions:

Vertices (0, ±5), foci (0, ±8)

Sum
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Solution

Vertices (0, ±5), foci (0, ±8)

Here, the vertices are on the y-axis.

Therefore, the equation of the hyperbola is of the form `y^2/a^2 - x^2/b^2 = 1`.

Since the vertices are (0, ±5), a = 5.

Since the foci are (0, ±8), c = 8.

We know that a2 + b2 = c2.

∴ 52 + b2 = 82

b2 = 64 - 25 = 39

Thus, the equation of the hyperbola is `y^2/25 - x^2/39 = 1`.

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Chapter 11: Conic Sections - Exercise 11.4 [Page 262]

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NCERT Mathematics [English] Class 11
Chapter 11 Conic Sections
Exercise 11.4 | Q 8 | Page 262
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