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Find the equation of the hyperbola satisfying the given conditions: Foci (0,±10), passing through (2, 3) - Mathematics

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Question

Find the equation of the hyperbola satisfying the given conditions:

Foci `(0, +- sqrt10)`, passing through (2, 3)

Sum
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Solution

Foci `(0, ±sqrt10)`

⇒ The transverse axis is along the y-axis.

and c = `sqrt10` or c2 = 10 = a2 + b2

∴ a2 + b2 = 10     ……(i)

Let the equation of hyperbola

`y^2/a^2 - x^2/b^2 = 1`

It goes from the point (2, 3)

∴ `9/a^2 - 4/b^2 = 1` or 9b2 − 4a2 = a2b2

By substituting the value of b2 from equation (i)

= 9(10 − a2) − 4a2 = a2 (10 − a2)

= 90 − 9a2 − 4a2 = 10a2 − a4

= a4 − 23a2 + 90 = 0

= a4 - 18a2 - 5a2 + 90 = 0

= (a2 − 18)(a2 − 5) = 0 

= a2 = 18 or 5

When, a2 = 18, b2 = 10 − a2

= 10 − 18

= −8

Hence, a2 ≠ 18

When a2 = 5, b2 = 10 − 5 = 5

∴ equation of hyperbola

`y^2/a^2 - x^2/b^2 = 1`

or `y^2/5 - x^2/5 = 1`

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Chapter 11: Conic Sections - Exercise 11.4 [Page 262]

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NCERT Mathematics [English] Class 11
Chapter 11 Conic Sections
Exercise 11.4 | Q 15 | Page 262

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