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प्रश्न
Find the equation of the hyperbola satisfying the given conditions:
Foci `(0, +- sqrt10)`, passing through (2, 3)
बेरीज
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उत्तर
Foci `(0, ±sqrt10)`
⇒ The transverse axis is along the y-axis.
and c = `sqrt10` or c2 = 10 = a2 + b2
∴ a2 + b2 = 10 ……(i)
Let the equation of hyperbola
`y^2/a^2 - x^2/b^2 = 1`
It goes from the point (2, 3)
∴ `9/a^2 - 4/b^2 = 1` or 9b2 − 4a2 = a2b2
By substituting the value of b2 from equation (i)
= 9(10 − a2) − 4a2 = a2 (10 − a2)
= 90 − 9a2 − 4a2 = 10a2 − a4
= a4 − 23a2 + 90 = 0
= a4 - 18a2 - 5a2 + 90 = 0
= (a2 − 18)(a2 − 5) = 0
= a2 = 18 or 5
When, a2 = 18, b2 = 10 − a2
= 10 − 18
= −8
Hence, a2 ≠ 18
When a2 = 5, b2 = 10 − 5 = 5
∴ equation of hyperbola
`y^2/a^2 - x^2/b^2 = 1`
or `y^2/5 - x^2/5 = 1`
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