मराठी

Find the equation of the hyperbola satisfying the given conditions: Foci (0,±10), passing through (2, 3) - Mathematics

Advertisements
Advertisements

प्रश्न

Find the equation of the hyperbola satisfying the given conditions:

Foci `(0, +- sqrt10)`, passing through (2, 3)

बेरीज
Advertisements

उत्तर

Foci `(0, ±sqrt10)`

⇒ The transverse axis is along the y-axis.

and c = `sqrt10` or c2 = 10 = a2 + b2

∴ a2 + b2 = 10     ……(i)

Let the equation of hyperbola

`y^2/a^2 - x^2/b^2 = 1`

It goes from the point (2, 3)

∴ `9/a^2 - 4/b^2 = 1` or 9b2 − 4a2 = a2b2

By substituting the value of b2 from equation (i)

= 9(10 − a2) − 4a2 = a2 (10 − a2)

= 90 − 9a2 − 4a2 = 10a2 − a4

= a4 − 23a2 + 90 = 0

= a4 - 18a2 - 5a2 + 90 = 0

= (a2 − 18)(a2 − 5) = 0 

= a2 = 18 or 5

When, a2 = 18, b2 = 10 − a2

= 10 − 18

= −8

Hence, a2 ≠ 18

When a2 = 5, b2 = 10 − 5 = 5

∴ equation of hyperbola

`y^2/a^2 - x^2/b^2 = 1`

or `y^2/5 - x^2/5 = 1`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 11: Conic Sections - Exercise 11.4 [पृष्ठ २६२]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
पाठ 11 Conic Sections
Exercise 11.4 | Q 15 | पृष्ठ २६२

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the equation of the hyperbola satisfying the given conditions:

Vertices (0, ±3), foci (0, ±5)


Find the equation of the hyperbola satisfying the given conditions:

Foci (0, ±13), the conjugate axis is of length 24.


Find the equation of the hyperbola satisfying the given conditions:

Foci `(+-3sqrt5, 0)`, the latus rectum is of length 8.


The equation of the directrix of a hyperbola is x − y + 3 = 0. Its focus is (−1, 1) and eccentricity 3. Find the equation of the hyperbola.


Find the equation of the hyperbola whose focus is (1, 1) directrix is 2x + y = 1 and eccentricity = \[\sqrt{3}\].


Find the equation of the hyperbola whose focus is (2, −1), directrix is 2x + 3y = 1 and eccentricity = 2 .


Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

16x2 − 9y2 = −144


Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

 4x2 − 3y2 = 36


Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

 3x2 − y2 = 4 


Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

2x2 − 3y2 = 5.


Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in  the distance between the foci = 16 and eccentricity = \[\sqrt{2}\].


Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in  the  conjugate axis is 5 and the distance between foci = 13 .


Find the equation of the hyperbola whose foci are (6, 4) and (−4, 4) and eccentricity is 2.


Find the equation of the hyperbola whose vertices are (−8, −1) and (16, −1) and focus is (17, −1).


Find the equation of the hyperbola whose foci at (± 2, 0) and eccentricity is 3/2. 


Find the equation of the hyperbola satisfying the given condition :

 vertices (0, ± 5), foci (0, ± 8)


Find the equation of the hyperbola satisfying the given condition :

vertices (0, ± 3), foci (0, ± 5)


find the equation of the hyperbola satisfying the given condition:

 vertices (± 7, 0), \[e = \frac{4}{3}\]


Show that the set of all points such that the difference of their distances from (4, 0) and (− 4,0) is always equal to 2 represents a hyperbola.


Write the distance between the directrices of the hyperbola x = 8 sec θ, y = 8 tan θ.


The difference of the focal distances of any point on the hyperbola is equal to


The foci of the hyperbola 9x2 − 16y2 = 144 are


Find the equation of the hyperbola with vertices at (0, ± 6) and e = `5/3`. Find its foci.


Find the equation of the hyperbola whose vertices are (± 6, 0) and one of the directrices is x = 4.


The length of the transverse axis along x-axis with centre at origin of a hyperbola is 7 and it passes through the point (5, –2). The equation of the hyperbola is ______.


The eccentricity of the hyperbola `x^2/a^2 - y^2/b^2` = 1 which passes through the points (3, 0) and `(3 sqrt(2), 2)` is ______.


Find the equation of the hyperbola with eccentricity `3/2` and foci at (± 2, 0).


Find the equation of the hyperbola with vertices (± 5, 0), foci (± 7, 0)


Find the equation of the hyperbola with vertices (0, ± 7), e = `4/3`


The locus of the point of intersection of lines `sqrt(3)x - y - 4sqrt(3)k` = 0 and `sqrt(3)kx + ky - 4sqrt(3)` = 0 for different value of k is a hyperbola whose eccentricity is 2.


The equation of the hyperbola with vertices at (0, ± 6) and eccentricity `5/3` is ______ and its foci are ______.


The distance between the foci of a hyperbola is 16 and its eccentricity is `sqrt(2)`. Its equation is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×