Question

Find the equation of a line whose intercepts on the x and y axes are given below

4, – 6

Answer 1

x intercept (a) = 4, y intercept (b) = – 6

Equation of a line is `x/"a" + y/"b"` = 1

`x/4 + y/(-6)` = 1

⇒ `x/4 - y/6` = 1  ...(L.C.M. of 4 and 6 is 12)

3x – 2y = 12

3x – 2y – 12 = 0

The equation of a line is 3x – 2y – 12 = 0